Home Competitions OMCC 2015 Problem 2
A sequence ( a n ) (a_n) ( a n ) of real numbers is defined by a 0 = 1 a_0=1 a 0 = 1 , a 1 = 2015 a_1=2015 a 1 = 2015 and for all n ≥ 1 n\geq1 n ≥ 1 , we have a n + 1 = n − 1 n + 1 a n − n − 2 n 2 + n a n − 1 . a_{n+1}=\frac{n-1}{n+1}a_n-\frac{n-2}{n^2+n}a_{n-1}. a n + 1 = n + 1 n − 1 a n − n 2 + n n − 2 a n − 1 . Calculate the value of a 1 a 2 − a 2 a 3 + a 3 a 4 − a 4 a 5 + … + a 2013 a 2014 − a 2014 a 2015 \frac{a_1}{a_2}-\frac{a_2}{a_3}+\frac{a_3}{a_4}-\frac{a_4}{a_5}+\ldots+\frac{a_{2013}}{a_{2014}}-\frac{a_{2014}}{a_{2015}} a 2 a 1 − a 3 a 2 + a 4 a 3 − a 5 a 4 + … + a 2014 a 2013 − a 2015 a 2014 .
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