OMCC 2013 Problem 2
- Day 1
Around a round table the people are seated in a clockwise order. Each person starts with a certain amount of coins (possibly none); there are a total of coins. Starting with and proceeding in clockwise order, each person does the following on their turn:
- If they have an even number of coins, they give all of their coins to their neighbor to the left.
- If they have an odd number of coins, they give their neighbor to the left an odd number of coins (at least and at most all of their coins) and keep the rest.
Prove that, repeating this procedure, there will necessarily be a point where one person has all of the coins.
Dataset text AI-MO AoPS. Quoted with source.
Solutions
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