olymmath

OMCC 2011 Problem 3

  • Day 1

A slip on an integer n≥2n\geq 2 is an operation that consists in choosing a prime divisor pp of nn and replacing nn by n+p2p.\frac{n+p^2}{p}.

Starting with an arbitrary integer n≥5n\geq 5 , we successively apply the slip operation on it. Show that one eventually reaches 55 , no matter the slips applied.

Dataset text AI-MO AoPS. Quoted with source.

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