OMCC 2008 Problem 3

There are 2008 bags numbered from 1 to 2008, with 2008 frogs in each one of them. Two people play in turns. A play consists in selecting a bag and taking out of it any number of frongs (at least one), leaving $x$ frogs in it ( $x\geq 0$ ). After each play, from each bag with a number higher than the selected one and having more than $x$ frogs, some frogs scape until there are $x$ frogs in the bag. The player that takes out the last frog from bag number 1 looses. Find and explain a winning strategy.