olymmath

CAPS 2016

Czech-Austrian-Polish-Slovak Match 2016.

Other problems

Problem 1

Let PP be a non-degenerate polygon with nn sides, where n>4n > 4 . Prove that there exist three distinct vertices A,B,CA, B, C of PP with the following property:If ℓ1,ℓ2,ℓ3\ell_1,\ell_2,\ell_3 are the lengths of the three polygonal chains into which A,B,CA, B, C break the perimeter of PP , then there is a triangle with side lengths ℓ1,ℓ2\ell_1,\ell_2 and ℓ3\ell_3 . Remark: By a non-degenerate polygon we mean a polygon in which every two sides are disjoint, apart from consecutive ones, which share only the common endpoint.(Poland)

Problem 3

Let nn be a positive integer. For a fi nite set MM of positive integers and each i∈{0,1,...,n−1}i \in \{0,1,..., n-1\} , we denote sis_i the number of non-empty subsets of MM whose sum of elements gives remainder ii after division by nn . We say that MM is " nn -balanced" if s0=s1=....=sn−1s_0 = s_1 =....= s_{n-1} . Prove that for every odd number nn there exists a non-empty nn -balanced subset of {0,1,...,n}\{0,1,..., n\} . For example if n=5n = 5 and M={1,3,4}M = \{1,3,4\} , we have s0=s1=s2=1,s3=s4=2s_0 = s_1 = s_2 = 1, s_3 = s_4 = 2 so MM is not 55 -balanced.(Czech Republic)

Problem 4

Find all quadruplets (a,b,c,d)(a, b, c, d) of real numbers satisfying the system (a+b)(a2+b2)=(c+d)(c2+d2)(a + b)(a^2 + b^2) = (c + d)(c^2 + d^2) (a+c)(a2+c2)=(b+d)(b2+d2)(a + c)(a^2 + c^2) = (b + d)(b^2 + d^2) (a+d)(a2+d2)=(b+c)(b2+c2)(a + d)(a^2 + d^2) = (b + c)(b^2 + c^2) (Slovakia)

Problem 5

Prove that for every non-negative integer nn there exist integers x,y,zx, y, z with gcd(x,y,z)=1gcd(x, y, z) = 1 , such that x2+y2+z2=32nx^2 + y^2 + z^2 = 3^{2^n} .(Poland)

Problem 6

Let ABCABC be an acute-angled triangle with AB<ACAB < AC . Tangent to its circumcircle Ω\Omega at AA intersects the line BCBC at DD . Let GG be the centroid of △ABC\triangle ABC and let AGAG meet Ω\Omega again at H≠AH \neq A . Suppose the line DGDG intersects the lines ABAB and ACAC at EE and FF , respectively. Prove that ∠EHG=∠GHF\angle EHG = \angle GHF .(Slovakia)