olymmath

CAPS 2014

Czech-Austrian-Polish-Slovak Match 2014.

Other problems

Problem 1

Prove that if the positive real numbers a,b,ca, b, c satisfy the equation a4+b4+c4+4a2b2c2=2(a2b2+a2c2+b2c2),a^4 + b^4 + c^4 + 4a^2b^2c^2 = 2 (a^2b^2 + a^2c^2 + b^2c^2), then there is a triangle ABCABC with internal angles α,β,γ\alpha, \beta, \gamma such that sin⁡α=a,sin⁡β=b,sin⁡γ=c.\sin \alpha = a, \sin \beta = b, \sin \gamma= c.

Problem 2

For the positive integers a,b,x1a, b, x_1 we construct the sequence of numbers (xn)n=1∞(x_n)_{n=1}^{\infty} such that xn=axn−1+bx_n = ax_{n-1} + b for each n≥2n \ge 2 . Specify the conditions for the given numbers a,ba, b and x1x_1 which are necessary and sufficient for all indexes m,nm, n to apply the implication m∣n⇒xm∣xnm | n \Rightarrow x_m | x_n .

(Jaromír Šimša)

Problem 3

Given is a convex ABCDABCD , which is ∣∠ABC∣=∣∠ADC∣=135∘|\angle ABC| = |\angle ADC|= 135^\circ . On the AB,ADAB, AD are also selected points M,NM, N such that ∣∠MCD∣=∣∠NCB∣=90∘|\angle MCD| = |\angle NCB| = 90^ \circ . The circumcircles of the triangles AMNAMN and ABDABD intersect for the second time at point K≠AK \ne A . Prove that lines AKAK and KCKC are perpendicular.

(Irán)

Problem 4

Let ABCABC be a triangle, and let PP be the midpoint of ACAC . A circle intersects AP,CP,BC,ABAP, CP, BC, AB sequentially at their inner points K,L,M,NK, L, M, N . Let SS be the midpoint of KLKL . Let also 2⋅∣AN∣⋅∣AB∣⋅∣CL∣=2⋅∣CM∣⋅∣BC∣⋅∣AK∣=∣AC∣⋅∣AK∣⋅∣CL∣.2 \cdot | AN |\cdot |AB |\cdot |CL | = 2 \cdot | CM | \cdot| BC | \cdot| AK| = | AC | \cdot| AK |\cdot |CL |. Prove that if P≠SP\ne S , then the intersection of KNKN and MLML lies on the perpendicular bisector of the PSPS .

(Jan Mazák)

Problem 5

Let all positive integers nn satisfy the following condition: for each non-negative integers k,mk, m with k+m≤nk + m \le n , the numbers (n−km)\binom{n-k}{m} and (n−mk)\binom{n-m}{k} leave the same remainder when divided by 22 .

(Poland)

PS. The translation was done using Google translate and in case it is not right, there is the original text in Slovak

Attachments:

slovak.png

Problem 6

Let n≥6n \ge 6 be an integer and FF be the system of the 33 -element subsets of the set {1,2,...,n}\{1, 2,...,n \} satisfying the following condition: for every 1≤i<j≤n1 \le i < j \le n there is at least ⌊13n⌋−1\lfloor \frac{1}{3} n \rfloor -1 subsets A∈FA\in F such that i,j∈Ai, j \in A . Prove that for some integer m≥1m \ge 1 exist the mutually disjoint subsets A1,A2,...,Am∈FA_1, A_2 , ... , A_m \in F also, that ∣A1∪A2∪...∪Am∣≥n−5|A_1\cup A_2 \cup ... \cup A_m |\ge n-5 (Poland)

PS. just in case my translation does not make sense, I leave the original in Slovak, in case someone understands something else

Attachments:

zc2.png