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CAPS 2004 Problem 5

    Points K,L,MK,L,M on the sides AB,BC,CAAB,BC,CA respectively of a triangle ABCABC satisfy AKKB=BLLC=CMMA\frac{AK}{KB} = \frac{BL}{LC} = \frac{CM}{MA} . Show that the triangles ABCABC and KLMKLM have a common orthocenter if and only if △ABC\triangle ABC is equilateral.

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