olymmath

CMO 2014 Problem 4

  • Paper

The quadrilateral ABCDA B C D is inscribed in a circle. The point PP lies in the interior of ABCDA B C D, and ∠PAB=∠PBC=∠PCD=∠PDA\angle P A B=\angle P B C=\angle P C D=\angle P D A. The lines ADA D and BCB C meet at QQ, and the lines ABA B and CDC D meet at RR. Prove that the lines PQP Q and PRP R form the same angle as the diagonals of ABCDA B C D.

Dataset text NuminaMath olympiads. Quoted with source.

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