olymmath

CMO 1998

Canadian Mathematical Olympiad 1998.

Paper

Problem 1

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Determine the number of real solutions aa to the equation: [ 12a ]+[ 13a ]+[ 15a ]=a.\left[\,\frac{1}{2} a\,\right]+\left[\,\frac{1}{3} a\,\right]+\left[\,\frac{1}{5} a\,\right] = a. Here, if xx is a real number, then [x ][ x\,] denotes the greatest integer that is less than or equal to xx .

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Problem 3

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Let nn be a natural number such that n≥2n \geq 2 . Show that 1n+1(1+13+⋅⋅⋅+12n−1)>1n(12+14+⋅⋅⋅+12n).\frac {1}{n + 1} \left( 1 + \frac {1}{3} + \cdot \cdot \cdot + \frac {1}{2n - 1} \right) > \frac {1}{n} \left( \frac {1}{2} + \frac {1}{4} + \cdot \cdot \cdot + \frac {1}{2n} \right).

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Problem 4

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Let ABCABC be a triangle with ∠BAC=40∘\angle{BAC} = 40^{\circ} and ∠ABC=60∘\angle{ABC}=60^{\circ} . Let DD and EE be the points lying on the sides ACAC and ABAB , respectively, such that ∠CBD=40∘\angle{CBD} = 40^{\circ} and ∠BCE=70∘\angle{BCE} = 70^{\circ} . Let FF be the point of intersection of the lines BDBD and CECE . Show that the line AFAF is perpendicular to the line BCBC .

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Problem 5

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Let mm be a positive integer. Define the sequence a0,a1,a2,⋯a_0, a_1, a_2, \cdots by a0=0,a1=m,a_0 = 0, a_1 = m, and an+1=m2an−an−1a_{n+1} = m^2a_n - a_{n-1} for n=1,2,3,⋯n = 1,2,3,\cdots . Prove that an ordered pair (a,b)(a,b) of non-negative integers, with a≤ba \leq b , gives a solution to the equation a2+b2ab+1=m2{ \frac{a^2 + b^2}{ab + 1} = m^2} if and only if (a,b)(a,b) is of the form (an,an+1)(a_n,a_{n+1}) for some n≥0n \geq 0 .

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