olymmath

CMO 1987 Problem 5

  • Paper

For every positive integer nn show that [4n+1]=[4n+2]=[4n+3]=[n+n+1][\sqrt{4n + 1}] = [\sqrt{4n + 2}] = [\sqrt{4n + 3}] = [\sqrt{n} + \sqrt{n + 1}] where [x][x] is the greatest integer less than or equal to xx (for example [2.3]=2[2.3] = 2 , [π]=3[\pi] = 3 , [5]=5[5] = 5 ).

Dataset text AI-MO AoPS. Quoted with source.

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