Home Competitions CMO 1969
CMO 1969
Canadian Mathematical Olympiad 1969.
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Problem 1
If a 1 / b 1 = a 2 / b 2 = a 3 / b 3 a_1/b_1=a_2/b_2=a_3/b_3 a 1 / b 1 = a 2 / b 2 = a 3 / b 3 and p 1 , p 2 , p 3 p_1,p_2,p_3 p 1 , p 2 , p 3 are not all zero, show that for all n ∈ N n\in\mathbb{N} n ∈ N , ( a 1 b 1 ) n = p 1 a 1 n + p 2 a 2 n + p 3 a 3 n p 1 b 1 n + p 2 b 2 n + p 3 b 3 n . \left(\frac{a_1}{b_1}\right)^n = \frac{p_1a_1^n+p_2a_2^n+p_3a_3^n}{p_1b_1^n+p_2b_2^n+p_3b_3^n}. ( b 1 a 1 ) n = p 1 b 1 n + p 2 b 2 n + p 3 b 3 n p 1 a 1 n + p 2 a 2 n + p 3 a 3 n .
Problem 4
Let A B C ABC A B C be an equilateral triangle, and P P P be an arbitrary point within the triangle. Perpendiculars P D , P E , P F PD,PE,PF P D , P E , P F are drawn to the three sides of the triangle. Show that, no matter where P P P is chosen, P D + P E + P F A B + B C + C A = 1 2 3 . \frac{PD+PE+PF}{AB+BC+CA}=\frac{1}{2\sqrt{3}}. A B + B C + C A P D + P E + P F = 2 3 1 .
Problem 5
Let A B C ABC A B C be a triangle with sides of length a a a , b b b and c c c . Let the bisector of the angle C C C cut A B AB A B in D D D . Prove that the length of C D CD C D is 2 a b cos C 2 a + b . \frac{2ab\cos \frac{C}{2}}{a+b}. a + b 2 ab cos 2 C .