Prove that the set of all divisors of a positive integer which is not a perfect square can be divided into pairs so that in each pair one number is divisible by another.
BY-MO 2018
Belarus Mathematical Olympiad 2018.
Other problems
For every integer prove the inequality where .
The bisector of angle of triangle intersects the side at . The point is the foot of the perpendicular from to and the point is the foot of perpendicular from to . The lines and meet at . Prove that is an altitude of triangle .
Three squares form the figure on the checkered plane as shown on the picture. (Neighboring squares are tpuching along the segment of length .)
Find all for which the figure can be covered with tiles and without overlapping.
The quadrilateral is inscribed in the parabola . It is known that angle , the dioganal is parallel to the axis and is the bisector of the angle BAD. Find the area of the quadrilateral if the length of the dioganal is equal to .
For all positive integers and prove the inequality
A point is choosen inside a triangle so that the length of segments , and are equal to , and , respectively. It is known that the feet of the perpendiculars from to the sides of the triangle are the vertices of an equilateral triangle. Find the value of the angle .
A positive integer is fixed. Numbers and are placed in all cells (exactly one number in any cell) of a table ( is a number of the rows in the table, is the number of the columns in it). We call a table nice if the following property is fulfilled: for any partition of the set of the rows of the table into two nonempty subsets 1 and 2 there exists a nonempty set of the columns such that on the intersection of any row from 1 with the columns from there are even number of while on the intersection of any row from 2 with the columns from there are odd number of . Find the greatest number of such that there exists at least one nice table.