olymmath

OBM 2008 Problem 5

    Prove that for all integers a>1a > 1 and b>1b > 1 there exists a function ff from the positive integers to the positive integers such that f(a⋅f(n))=b⋅nf(a\cdot f(n)) = b\cdot n for all nn positive integer.

    Dataset text AI-MO AoPS. Quoted with source.

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