olymmath

OBM 1979 Problem 4

    Show that the number of positive integer solutions to x1+23x2+33x3+…+103x10=3025x_1 + 2^3x_2 + 3^3x_3 + \ldots + 10^3x_{10} = 3025 () equals the number of non-negative integer solutions to the equation y1+23y2+33y3+…+103y10=0y_1 + 2^3y_2 + 3^3y_3 + \ldots + 10^3y_{10} = 0 . Hence show that () has a unique solution in positive integers and find it.

    Dataset text AI-MO AoPS. Quoted with source.

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