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BALTIC-WAY 2014 Problem 1

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cos⁡(56∘)⋅cos⁡(2⋅56∘)⋅cos⁡(22⋅56∘)⋅…⋅cos⁡(223⋅56∘)=1224\cos \left(56^{\circ}\right) \cdot \cos \left(2 \cdot 56^{\circ}\right) \cdot \cos \left(2^{2} \cdot 56^{\circ}\right) \cdot \ldots \cdot \cos \left(2^{23} \cdot 56^{\circ}\right)=\frac{1}{2^{24}}

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{1}{2^{24}}

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