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BALTIC-WAY 2005 Problem 11

    Let the points DD and EE lie on the sides BCB C and ACA C, respectively, of the triangle ABCA B C, satisfying BD=AEB D=A E. The line joining the circumcentres of the triangles ADCA D C and BECB E C meets the lines ACA C and BCB C at KK and LL, respectively. Prove that KC=LCK C=L C.

    Dataset text NuminaMath olympiads. Quoted with source.

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