olymmath

BALTIC-WAY 2005 Problem 10

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Let m=30030=2⋅3⋅5⋅7⋅11⋅13m=30030=2 \cdot 3 \cdot 5 \cdot 7 \cdot 11 \cdot 13 and let MM be the set of its positive divisors which have exactly two prime factors. Determine the minimal integer nn with the following property: for any choice of numbers from MM, there exist three numbers a,b,ca, b, c among them satisfying a⋅b⋅c=ma \cdot b \cdot c=m.

Dataset text NuminaMath olympiads. Quoted with source.

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