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BALTIC-WAY 2001 Problem 7

    Given a parallelogram ABCDA B C D. A circle passing through AA meets the line segments AB,ACA B, A C and ADA D at inner points M,K,NM, K, N, respectively. Prove that

    ∣AB∣⋅∣AM∣+∣AD∣⋅∣AN∣=∣AK∣⋅∣AC∣.|A B| \cdot|A M|+|A D| \cdot|A N|=|A K| \cdot|A C| .

    Dataset text NuminaMath olympiads. Quoted with source.

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