olymmath

BALTIC-WAY 1997 Problem 5

    In a sequence u0,u1,…u_{0}, u_{1}, \ldots of positive integers, u0u_{0} is arbitrary, and for any non-negative integer nn,

    un+1={12un for even una+un for odd unu_{n+1}= \begin{cases}\frac{1}{2} u_{n} & \text { for even } u_{n} \\ a+u_{n} & \text { for odd } u_{n}\end{cases}

    where aa is a fixed odd positive integer. Prove that the sequence is periodic from a certain step.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator baltic-way/1997/p5 · Tag WXTEJY5E28 · Edit this page on GitHub · Keys: j next, k previous