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BALTIC-WAY 1992 Problem 6

  • Answer

Prove that the product of the 99 numbers of the form k3−1k3+1\frac{k^{3}-1}{k^{3}+1} where k=2,3,…,100k=2,3, \ldots, 100, is greater than 23\frac{2}{3}.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{1 \cdot 2 \cdot\left(100^{2}+100+1\right)}{100 \cdot 101 \cdot\left(1^{2}+1+1\right)}>\frac{2}{3}

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