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BALKAN 1995 Problem 2

  • Paper

The circles C1(O1,r1)\mathcal C_1(O_1, r_1) and C2(O2,r2)\mathcal C_2(O_2, r_2) , r2>r1r_2 > r_1 , intersect at AA and BB such that ∠O1AO2=90∘\angle O_1AO_2 = 90^\circ . The line O1O2O_1O_2 meets C1\mathcal C_1 at CC and DD , and C2\mathcal C_2 at EE and FF (in the order CC , EE , DD , FF ). The line BEBE meets C1\mathcal C_1 at KK and ACAC at MM , and the line BDBD meets C2\mathcal C_2 at LL and AFAF at NN . Prove that r2r1=KEKM⋅LNLD.\frac{ r_2}{r_1} = \frac{KE}{KM} \cdot \frac{LN}{LD} . Greece

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