olymmath

BALKAN-SL 2020

Balkan MO Shortlist 2020.

Other problems

A2

Given are positive reals a,b,ca, b, c , such that 1a+1b+1c=3\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=3 . Prove that a+bc+b+ca+c+ab3≤a+b+c−12\frac{\sqrt{a+\frac{b}{c}}+\sqrt{b+\frac{c}{a}}+\sqrt{c+\frac{a}{b}}}{3}\leq \frac{a+b+c-1}{\sqrt{2}} .

Albania

A3

Let P(x),Q(x)P(x), Q(x) be distinct polynomials of degree 20202020 with non-zero coefficients. Suppose that they have rr common real roots counting multiplicity and ss common coefficients. Determine the maximum possible value of r+sr + s .

Demetres Christofides, Cyprus

A4

Let P(x)=x3+ax2+bx+1P(x) = x^3 + ax^2 + bx + 1 be a polynomial with real coefficients and three real roots ρ1\rho_1 , ρ2\rho_2 , ρ3\rho_3 such that ∣ρ1∣<∣ρ2∣<∣ρ3∣|\rho_1| < |\rho_2| < |\rho_3| . Let AA be the point where the graph of P(x)P(x) intersects yy′yy' and the point B(ρ1,0)B(\rho_1, 0) , C(ρ2,0)C(\rho_2, 0) , D(ρ3,0)D(\rho_3, 0) . If the circumcircle of △ABD\vartriangle ABD intersects yy′yy' for a second time at EE , find the minimum value of the length of the segment ECEC and the polynomials for which this is attained.

Brazitikos Silouanos, Greece

C1

Let s≥2s \geq 2 and n≥k≥2n \geq k \geq 2 be integes, and let AA be a subset of {1,2,...,n}k\{1, 2, . . . , n\}^k of size at least 2sk2nk−22sk^2n^{k-2} such that any two members of AA share some entry. Prove that there are an integer p≤kp \leq k and s+2s+2 members A1,A2,...,As+2A_1, A_2, . . . , A_{s+2} of AA such that AiA_i and AjA_j share the pp -th entry alone, whenever ii and jj are distinct.

Miroslav Marinov, Bulgaria

C3

Odin and Evelyn are playing a game, Odin going first. There are initially 3k3k empty boxes, for some given positive integer kk . On each player's turn, they can write a non-negative integer in an empty box, or erase a number in a box and replace it with a strictly smaller non-negative integer. However, Odin is only ever allowed to write odd numbers, and Evelyn is only allowed to write even numbers. The game ends when either one of the players cannot move, in which case the other player wins; or there are exactly kk boxes with the number 00 , in which case Evelyn wins if all other boxes contain the number 11 , and Odin wins otherwise. Who has a winning strategy? Agnijo Banerjee ,United KingdomAgnijo \ Banerjee \ , United \ Kingdom

C4

A strategical video game consists of a map of finitely many towns. In each town there are kk directions, labelled from 11 through kk . One of the towns is designated as initial, and one - as terminal. Starting from the initial town the hero of the game makes a finite sequence of moves. At each move the hero selects a direction from the current town. This determines the next town he visits and a certain positive amount of points he receives. Two strategical video games are equivalent if for every sequence of directions the hero can reach the terminal town from the initial in one game, he can do so in the other game, and, in addition, he accumulates the same amount of points in both games. For his birthday John receives two strategical video games - one with NN towns and one with MM towns. He claims they are equivalent. Marry is convinced they are not. Marry is right. Prove that she can provide a sequence of at most N+MN +M directions that shows the two games are indeed not equivalent.

Stefan Gerdjikov, Bulgaria

G2

Let G,HG, H be the centroid and orthocentre of △ABC\vartriangle ABC which has an obtuse angle at ∠B\angle B . Let ω\omega be the circle with diameter AGAG . ω\omega intersects ⊙(ABC)\odot(ABC) again at L≠AL \ne A . The tangent to ω\omega at LL intersects ⊙(ABC)\odot(ABC) at K≠LK \ne L . Given that AG=GHAG = GH , prove ∠HKG=90o\angle HKG = 90^o . Sam Bealing, United Kingdom

G3

Let ABCABC be a triangle. On the sides BCBC , CACA , ABAB of the triangle, construct outwardly three squares with centres OaO_a , ObO_b , OcO_c respectively. Let ω\omega be the circumcircle of △OaObOc\vartriangle O_aO_bO_c . Given that AA lies on ω\omega , prove that the centre of ω\omega lies on the perimeter of △ABC\vartriangle ABC .

Sam Bealing, United Kingdom

G4

Let MAZNMAZN be an isosceles trapezium inscribed in a circle (c)(c) with centre OO . Assume that MNMN is a diameter of (c)(c) and let BB be the midpoint of AZAZ . Let (ϵ)(\epsilon) be the perpendicular line on AZAZ passing through AA . Let CC be a point on (ϵ)(\epsilon) , let EE be the point of intersection of CBCB with (c)(c) and assume that AEAE is perpendicular to CBCB . Let DD be the point of intersection of CZCZ with (c)(c) and let FF be the antidiametric point of DD on (c)(c) . Let PP be the point of intersection of FEFE and CZCZ . Assume that the tangents of (c)(c) at the points MM and ZZ meet the lines AZAZ and PAPA at the points KK and TT respectively. Prove that OKOK is perpendicular to TMTM .

Theoklitos Parayiou, Cyprus

G5

Let ABCABC be an isosceles triangle with AB=ACAB = AC and ∠A=45o\angle A = 45^o . Its circumcircle (c)(c) has center O,MO, M is the midpoint of BCBC and DD is the foot of the perpendicular from CC to ABAB . With center CC and radius CDCD we draw a circle which internally intersects ACAC at the point FF and the circle (c)(c) at the points ZZ and EE , such that ZZ lies on the small arc BCBC and EE on the small arc ACAC . Prove that the lines ZEZE , COCO , FMFM are concurrent.

Brazitikos Silouanos, Greece

N1

Determine all positive integers nn such that a2+n2b2−n2\frac{a^2+n^2}{b^2-n^2} is a positive integer for some a,b∈Na,b\in \mathbb{N} . TurkeyTurkey

N2

A number of NN children are at a party and they sit in a circle to play a game of Pass and Parcel. Because the host has no other form of entertainment, the parcel has infinitely many layers. On turn ii , starting with i=1i=1 , the following two things happen in order:(1)(1) The parcel is passed i2i^2 positions clockwise; and**(2)(2)** The child currently holding the parcel unwraps a layer and claims the prize inside. For what values of NN will every chidren receive a prize?

Patrick WinterUnited KingdomPatrick \ Winter United \ Kingdom

N3

Given an integer k≥2k\geq 2 , determine all functions ff from the positive integers into themselves such that f(x1)!+f(x2)!+⋯f(xk)!f(x_1)!+f(x_2)!+\cdots f(x_k)! is divisibe by x1!+x2!+⋯xk!x_1!+x_2!+\cdots x_k! for all positive integers x1,x2,⋯xkx_1,x_2,\cdots x_k . AlbaniaAlbania

N5

Consider an integer n≥2n\geq 2 and an odd prime pp . Let UU be the set of all positive integers (( strictly )) less than pnp^n that are not divisible by pp , and let NN be the number of elements of UU . Does there exist permutation a1,a2,⋯aNa_1,a_2,\cdots a_N of the numbers in UU such that the sum ∑k=1Nakak+1\sum_{k=1}^N a_ka_{k+1} ,where aN+1=a1a_{N+1}=a_1 , be divisible by pn−1p^{n-1} but not by pnp^n ? Alexander IvanovBulgariaAlexander \ Ivanov Bulgaria