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BALKAN-SL 2018 G4

    A quadrilateral ABCDABCD is inscribed in a circle kk where ABAB >> CDCD, and ABAB is not paralel to CDCD. Point MM is the intersection of diagonals ACAC and BDBD, and the perpendicular from MM to ABAB intersects the segment ABAB at a point EE. If EMEM bisects the angle CEDCED prove that ABAB is diameter of kk. Proposed by Emil Stoyanov,Bulgaria

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