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AZ-MO 2015 Problem 5

    In the convex quadrilateral ABCDABCD angle ∠BAD=90\angle{BAD}=90 , ∠BAC=2⋅∠BDC\angle{BAC}=2\cdot\angle{BDC} and ∠DBA+∠DCB=180\angle{DBA}+\angle{DCB}=180 . Then find the angle ∠DBA\angle{DBA}

    Dataset text AI-MO AoPS. Quoted with source.

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