olymmath

AUSTRIAN-POLISH 1991 Problem 8

    Consider the system of congruences {xy≡−1 (modz)yz≡1(modx)zx≡1(mody)\begin{cases} xy \equiv - 1 \, (mod z) yz \equiv 1 (mod x) zx \equiv 1 (mod y)\end {cases} Find the number of triples (x,y,z)(x,y, z) of distinct positive integers satisfying this system such that one of the numbers x,y,zx,y, z equals 1919 .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator austrian-polish/1991/p8 · Tag 8J6J275TEN · Edit this page on GitHub · Keys: j next, k previous