olymmath

ÖMO 2007 Problem 5

    38th Austrian Mathematical Olympiad 2007, round 3 problem 5

    Given is a convex nn -gon with a triangulation, that is a partition into triangles through diagonals that don't cut each other. Show that it's always possible to mark the nn corners with the digits of the number 20072007 such that every quadrilateral consisting of 22 neighbored (along an edge) triangles has got 99 as the sum of the numbers on its 44 corners.

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator at-oemo/2007/p5 · Tag P984F9Z147 · Edit this page on GitHub · Keys: j next, k previous