olymmath

AT-OEMO-FED1 2003 Problem 4

    In a parallelogram ABCDABCD , points EE and FF are the midpoints of ABAB and BCBC , respectively, and PP is the intersection of ECEC and FDFD . Prove that the segments AP,BP,CPAP,BP,CP and DPDP divide the parallelogram into four triangles whose areas are in the ratio 1:2:3:41 : 2 : 3 : 4 .

    Dataset text AI-MO AoPS. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Similar problems

    These problems have the most words in common with this statement.

    Locator at-oemo-fed1/2003/p4 · Tag EH0YR6J9JB · Edit this page on GitHub · Keys: j next, k previous