olymmath

APMO 1996

Asian Pacific Mathematics Olympiad 1996.

Paper

Problem 1

  • Paper

Let ABCDABCD be a quadrilateral AB=BC=CD=DAAB = BC = CD = DA . Let MNMN and PQPQ be two segments perpendicular to the diagonal BDBD and such that the distance between them is d>BD2d > \frac{BD}{2} , with M∈ADM \in AD , N∈DCN \in DC , P∈ABP \in AB , and Q∈BCQ \in BC . Show that the perimeter of hexagon AMNCQPAMNCQP does not depend on the position of MNMN and PQPQ so long as the distance between them remains constant.

Answer, solutions and source

Problem 2

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Let mm and nn be positive integers such that n≤mn \leq m . Prove that 2nn!≤(m+n)!(m−n)!≤(m2+m)n2^n n! \leq \frac{(m+n)!}{(m-n)!} \leq (m^2 + m)^n

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Problem 4

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The National Marriage Council wishes to invite nn couples to form 17 discussion groups under the following conditions:

(1) All members of a group must be of the same sex; i.e. they are either all male or all female.

(2) The difference in the size of any two groups is 0 or 1.

(3) All groups have at least 1 member.

(4) Each person must belong to one and only one group.

Find all values of nn , n≤1996n \leq 1996 , for which this is possible. Justify your answer.

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Problem 5

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Let aa , bb , cc be the lengths of the sides of a triangle. Prove that a+b−c+b+c−a+c+a−b≤a+b+c\sqrt{a+b-c} + \sqrt{b+c-a} + \sqrt{c+a-b} \leq \sqrt{a} + \sqrt{b} + \sqrt{c} and determine when equality occurs.

Answer, solutions and source