olymmath

AMC 8 2015 Problem 16

  • Paper

In a middle-school mentoring program, a number of the sixth graders are paired with a ninth-grade student as a buddy. No ninth grader is assigned more than one sixth-grade buddy. If 13\frac{1}{3} of all the ninth graders are paired with 25\frac{2}{5} of all the sixth graders, what fraction of the total number of sixth and ninth graders have a buddy? (A) 215(B) 411(C) 1130(D) 38(E) 1115\textbf{(A) } \frac{2}{15} \textbf{(B) } \frac{4}{11} \textbf{(C) } \frac{11}{30} \textbf{(D) } \frac{3}{8} \textbf{(E) } \frac{11}{15}

Dataset text NuminaMath-1.5. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc8/2015/p16 · Tag BJPPMYNNHB · Edit this page on GitHub · Keys: j next, k previous