olymmath

AMC 8 2007 Problem 18

  • Paper

The product of the two 9999-digit numbers 303,030,303,...,030,303303,030,303,...,030,303 and 505,050,505,...,050,505505,050,505,...,050,505 has thousands digit AA and units digit BB. What is the sum of AA and BB? (A) 3(B) 5(C) 6(D) 8(E) 10\mathrm{(A)}\ 3 \mathrm{(B)}\ 5 \mathrm{(C)}\ 6 \mathrm{(D)}\ 8 \mathrm{(E)}\ 10

Dataset text NuminaMath-1.5. Quoted with source.

Show the answer

8

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc8/2007/p18 · Tag T55XV1CNNF · Edit this page on GitHub · Keys: j next, k previous