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AMC 8 1996 Problem 8

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Points AA and BB are 10 units apart. Points BB and CC are 4 units apart. Points CC and DD are 3 units apart. If AA and DD are as close as possible, then the number of units between them is (A) 0(B) 3(C) 9(D) 11(E) 17\text{(A)}\ 0 \text{(B)}\ 3 \text{(C)}\ 9 \text{(D)}\ 11 \text{(E)}\ 17

Dataset text NuminaMath-1.5. Quoted with source.

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