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AMC 8 1996 Problem 25

  • Paper

A point is chosen at random from within a circular region. What is the probability that the point is closer to the center of the region than it is to the boundary of the region? (A)14(B)13(C)12(D)23(E)34\text{(A)}\frac{1}{4} \text{(B)}\frac{1}{3} \text{(C)}\frac{1}{2} \text{(D)}\frac{2}{3} \text{(E)}\frac{3}{4}

Dataset text NuminaMath-1.5. Quoted with source.

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\frac{1}{4}

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