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AMC 8 1996 Problem 16

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1−2−3+4+5−6−7+8+9−10−11+⋯+1992+1993−1994−1995+1996=1-2-3+4+5-6-7+8+9-10-11+\cdots + 1992+1993-1994-1995+1996= (A) −998(B) −1(C) 0(D) 1(E) 998\text{(A)}\ -998 \text{(B)}\ -1 \text{(C)}\ 0 \text{(D)}\ 1 \text{(E)}\ 998

Dataset text NuminaMath-1.5. Quoted with source.

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