AMC 8 1995 Problem 24

In parallelogram $ABCD$, $\overline{DE}$ is the altitude to the base $\overline{AB}$ and $\overline{DF}$ is the altitude to the base $\overline{BC}$. [Note: Both pictures represent the same parallelogram.] If $DC=12$, $EB=4$, and $DE=6$, then $DF=$

$\text{(A)}\ 6.4 \text{(B)}\ 7 \text{(C)}\ 7.2 \text{(D)}\ 8 \text{(E)}\ 10$