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AMC 8 1993 Problem 4

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1000×1993×0.1993×10=1000\times 1993 \times 0.1993 \times 10 = (A) 1.993×103(B) 1993.1993(C) (199.3)2(D) 1,993,001.993(E) (1993)2\text{(A)}\ 1.993\times 10^3 \text{(B)}\ 1993.1993 \text{(C)}\ (199.3)^2 \text{(D)}\ 1,993,001.993 \text{(E)}\ (1993)^2

Dataset text NuminaMath-1.5. Quoted with source.

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(1993)^2

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