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AMC 8 1991 Problem 7

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The value of (487,000)(12,027,300)+(9,621,001)(487,000)(19,367)(.05)\frac{(487,000)(12,027,300)+(9,621,001)(487,000)}{(19,367)(.05)} is closest to (A) 10,000,000(B) 100,000,000(C) 1,000,000,000(D) 10,000,000,000(E) 100,000,000,000\text{(A)}\ 10,000,000 \text{(B)}\ 100,000,000 \text{(C)}\ 1,000,000,000 \text{(D)}\ 10,000,000,000 \text{(E)}\ 100,000,000,000

Dataset text NuminaMath-1.5. Quoted with source.

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10,000,000,000

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