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AMC 8 1989 Problem 13

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97×53=\frac{9}{7\times 53} = (A) .9.7×53(B) .9.7×.53(C) .9.7×5.3(D) .97×.53(E) .09.07×.53\text{(A)}\ \frac{.9}{.7\times 53} \text{(B)}\ \frac{.9}{.7\times .53} \text{(C)}\ \frac{.9}{.7\times 5.3} \text{(D)}\ \frac{.9}{7\times .53} \text{(E)}\ \frac{.09}{.07\times .53}

Dataset text NuminaMath-1.5. Quoted with source.

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