olymmath

AMC 8 1989 Problem 1

  • Paper

(1+11+21+31+41)+(9+19+29+39+49)=(1+11+21+31+41)+(9+19+29+39+49)= (A) 150(B) 199(C) 200(D) 249(E) 250\text{(A)}\ 150 \text{(B)}\ 199 \text{(C)}\ 200 \text{(D)}\ 249 \text{(E)}\ 250

Dataset text NuminaMath-1.5. Quoted with source.

Show the answer

250

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc8/1989/p1 · Tag 2WBC1CXAAQ · Edit this page on GitHub · Keys: j next, k previous