AMC 12 2024a Problem 19

Cyclic quadrilateral $ABCD$ has lengths $BC=CD=3$ and $DA=5$ with $\angle CDA=120^\circ$. What is the length of the shorter diagonal of $ABCD$?

$\textbf{(A) }\frac{31}7 \textbf{(B) }\frac{33}7 \textbf{(C) }5 \textbf{(D) }\frac{39}7 \textbf{(E) }\frac{41}7$