olymmath

AMC 12 2024a Problem 13

  • Paper

The graph of y=ex+1+e−x−2y=e^{x+1}+e^{-x}-2 has an axis of symmetry. What is the reflection of the point (−1,12)(-1,\tfrac{1}{2}) over this axis?

(A) (−1,−32)(B) (−1,0)(C) (−1,12)(D) (0,12)(E) (3,12)\textbf{(A) }\left(-1,-\frac{3}{2}\right) \textbf{(B) }(-1,0) \textbf{(C) }\left(-1,\tfrac{1}{2}\right) \textbf{(D) }\left(0,\frac{1}{2}\right) \textbf{(E) }\left(3,\frac{1}{2}\right)

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

D

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2024a/p13 · Tag H9ZZ69W67M · Edit this page on GitHub · Keys: j next, k previous