olymmath

AMC 12 2023a Problem 23

  • Paper

How many ordered pairs of positive real numbers (a,b)(a,b) satisfy the equation (1+2a)(2+2b)(2a+b)=32ab?(1+2a)(2+2b)(2a+b) = 32ab?

(A) 0(B) 1(C) 2(D) 3(E) an infinite number\textbf{(A) }0 \textbf{(B) }1 \textbf{(C) }2 \textbf{(D) }3 \textbf{(E) }\text{an infinite number}

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

B

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2023a/p23 · Tag YZJ0PRRYTP · Edit this page on GitHub · Keys: j next, k previous