olymmath

AMC 12 2020a Problem 2

  • Paper

The acronym AMC is shown in the rectangular grid below with grid lines spaced 11 unit apart. In units, what is the sum of the lengths of the line segments that form the acronym AMC??

import olympiad;
unitsize(25);
for (int i = 0; i < 3; ++i) {
for (int j = 0; j < 9; ++j) {
pair A = (j,i);

}
}
for (int i = 0; i < 3; ++i) {
for (int j = 0; j < 9; ++j) {
if (j != 8) {
draw((j,i)--(j+1,i), dashed);
}
if (i != 2) {
draw((j,i)--(j,i+1), dashed);
}
}
}
draw((0,0)--(2,2),linewidth(2));
draw((2,0)--(2,2),linewidth(2));
draw((1,1)--(2,1),linewidth(2));
draw((3,0)--(3,2),linewidth(2));
draw((5,0)--(5,2),linewidth(2));
draw((4,1)--(3,2),linewidth(2));
draw((4,1)--(5,2),linewidth(2));
draw((6,0)--(8,0),linewidth(2));
draw((6,2)--(8,2),linewidth(2));
draw((6,0)--(6,2),linewidth(2));

(A) 17(B) 15+22(C) 13+42(D) 11+62(E) 21\textbf{(A) } 17 \textbf{(B) } 15 + 2\sqrt{2} \textbf{(C) } 13 + 4\sqrt{2} \textbf{(D) } 11 + 6\sqrt{2} \textbf{(E) } 21

Dataset text AMC 12 2000 to 2025. Quoted with source.

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C

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