olymmath

AMC 12 2018a Problem 3

  • Paper

How many ways can a student schedule 33 mathematics courses -- algebra, geometry, and number theory -- in a 66-period day if no two mathematics courses can be taken in consecutive periods? (What courses the student takes during the other 33 periods is of no concern here.)

(A) 3(B) 6(C) 12(D) 18(E) 24\textbf{(A) }3 \textbf{(B) }6 \textbf{(C) }12 \textbf{(D) }18 \textbf{(E) }24

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

E

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2018a/p3 · Tag 5TNT1YYEYF · Edit this page on GitHub · Keys: j next, k previous