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AMC 12 2014a Problem 23

  • Paper

The fraction 1992=0.bn−1bn−2…b2b1b0‾,\dfrac1{99^2}=0.\overline{b_{n-1}b_{n-2}\ldots b_2b_1b_0}, where nn is the length of the period of the repeating decimal expansion. What is the sum b0+b1+⋯+bn−1b_0+b_1+\cdots+b_{n-1}?

(A) 874(B) 883(C) 887(D) 891(E) 892\textbf{(A) }874 \textbf{(B) }883 \textbf{(C) }887 \textbf{(D) }891 \textbf{(E) }892

Dataset text AMC 12 2000 to 2025. Quoted with source.

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B

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