olymmath

AMC 12 2010b Problem 9

  • Paper

Let nn be the smallest positive integer such that nn is divisible by 2020, n2n^2 is a perfect cube, and n3n^3 is a perfect square. What is the number of digits of nn?

\textbf{(A)}\ 3 \textbf{(B)}\ 4 \textbf{(C)}\ 5 \textbf{(D)}\ 6 \textbf{(E)}\ 7

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

E

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2010b/p9 · Tag 6YWQ8MD15X · Edit this page on GitHub · Keys: j next, k previous