olymmath

AMC 12 2010a Problem 23

  • Paper

The number obtained from the last two nonzero digits of 90!90! is equal to nn. What is nn?

\textbf{(A)}\ 12 \textbf{(B)}\ 32 \textbf{(C)}\ 48 \textbf{(D)}\ 52 \textbf{(E)}\ 68

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

A

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2010a/p23 · Tag DBF9S526VV · Edit this page on GitHub · Keys: j next, k previous