olymmath

AMC 12 2005b Problem 25

  • Paper

Six ants simultaneously stand on the six vertices of a regular octahedron, with each ant at a different vertex. Simultaneously and independently, each ant moves from its vertex to one of the four adjacent vertices, each with equal probability. What is the probability that no two ants arrive at the same vertex?

(A) 5256(B) 211024(C) 11512(D) 231024(E) 3128\mathrm{(A)}\ \frac {5}{256} \mathrm{(B)}\ \frac {21}{1024} \mathrm{(C)}\ \frac {11}{512} \mathrm{(D)}\ \frac {23}{1024} \mathrm{(E)}\ \frac {3}{128}

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

A

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2005b/p25 · Tag B9P1WWH40Q · Edit this page on GitHub · Keys: j next, k previous