olymmath

AMC 12 2005b Problem 10

  • Paper

The first term of a sequence is 20052005. Each succeeding term is the sum of the cubes of the digits of the previous term. What is the 2005th2005^{\text{th}} term of the sequence?

\textbf{(A)}\ 29 \textbf{(B)}\ 55 \textbf{(C)}\ 85 \textbf{(D)}\ 133 \textbf{(E)}\ 250

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

E

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2005b/p10 · Tag KHKX68V9SX · Edit this page on GitHub · Keys: j next, k previous