olymmath

AMC 12 2003b Problem 1

  • Paper

Which of the following is the same as

2−4+6−8+10−12+143−6+9−12+15−18+21?\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}?

(A) −1(B) −23(C) 23(D) 1(E) 143\text {(A) } -1 \text {(B) } -\frac{2}{3} \text {(C) } \frac{2}{3} \text {(D) } 1 \text {(E) } \frac{14}{3}

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

C

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Similar problems

These problems have the most words in common with this statement.

Locator amc12/2003b/p1 · Tag NANBFCBKPN · Edit this page on GitHub · Keys: j next, k previous