olymmath

AMC 12 2003a Problem 10

  • Paper

Al, Bert, and Carl are the winners of a school drawing for a pile of Halloween candy, which they are to divide in a ratio of 3:2:13:2:1, respectively. Due to some confusion they come at different times to claim their prizes, and each assumes he is the first to arrive. If each takes what he believes to be the correct share of candy, what fraction of the candy goes unclaimed?

(A) 118(B) 16(C) 29(D) 518(E) 512\mathrm{(A) \ } \frac{1}{18} \mathrm{(B) \ } \frac{1}{6} \mathrm{(C) \ } \frac{2}{9} \mathrm{(D) \ } \frac{5}{18} \mathrm{(E) \ } \frac{5}{12}

Dataset text AMC 12 2000 to 2025. Quoted with source.

Show the answer

D

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator amc12/2003a/p10 · Tag CT6KTDJCRB · Edit this page on GitHub · Keys: j next, k previous